Optimal. Leaf size=140 \[ -\frac {8 a^3 (i A+B)}{3 f (c-i c \tan (e+f x))^{3/2}}+\frac {8 a^3 (i A+2 B)}{c f \sqrt {c-i c \tan (e+f x)}}+\frac {2 a^3 (i A+5 B) \sqrt {c-i c \tan (e+f x)}}{c^2 f}-\frac {2 a^3 B (c-i c \tan (e+f x))^{3/2}}{3 c^3 f} \]
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Rubi [A]
time = 0.15, antiderivative size = 140, normalized size of antiderivative = 1.00, number of steps
used = 3, number of rules used = 2, integrand size = 43, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.047, Rules used = {3669, 78}
\begin {gather*} \frac {2 a^3 (5 B+i A) \sqrt {c-i c \tan (e+f x)}}{c^2 f}+\frac {8 a^3 (2 B+i A)}{c f \sqrt {c-i c \tan (e+f x)}}-\frac {8 a^3 (B+i A)}{3 f (c-i c \tan (e+f x))^{3/2}}-\frac {2 a^3 B (c-i c \tan (e+f x))^{3/2}}{3 c^3 f} \end {gather*}
Antiderivative was successfully verified.
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Rule 78
Rule 3669
Rubi steps
\begin {align*} \int \frac {(a+i a \tan (e+f x))^3 (A+B \tan (e+f x))}{(c-i c \tan (e+f x))^{3/2}} \, dx &=\frac {(a c) \text {Subst}\left (\int \frac {(a+i a x)^2 (A+B x)}{(c-i c x)^{5/2}} \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac {(a c) \text {Subst}\left (\int \left (\frac {4 a^2 (A-i B)}{(c-i c x)^{5/2}}-\frac {4 a^2 (A-2 i B)}{c (c-i c x)^{3/2}}+\frac {a^2 (A-5 i B)}{c^2 \sqrt {c-i c x}}+\frac {i a^2 B \sqrt {c-i c x}}{c^3}\right ) \, dx,x,\tan (e+f x)\right )}{f}\\ &=-\frac {8 a^3 (i A+B)}{3 f (c-i c \tan (e+f x))^{3/2}}+\frac {8 a^3 (i A+2 B)}{c f \sqrt {c-i c \tan (e+f x)}}+\frac {2 a^3 (i A+5 B) \sqrt {c-i c \tan (e+f x)}}{c^2 f}-\frac {2 a^3 B (c-i c \tan (e+f x))^{3/2}}{3 c^3 f}\\ \end {align*}
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Mathematica [A]
time = 3.15, size = 168, normalized size = 1.20 \begin {gather*} \frac {a^3 (15 (i A+3 B) \cos (e+f x)+(7 i A+23 B) \cos (3 (e+f x))+2 (9 A-26 i B+(9 A-25 i B) \cos (2 (e+f x))) \sin (e+f x)) (\cos (2 e+5 f x)+i \sin (2 e+5 f x)) (A+B \tan (e+f x)) \sqrt {c-i c \tan (e+f x)}}{3 c^2 f (\cos (f x)+i \sin (f x))^3 (A \cos (e+f x)+B \sin (e+f x))} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.26, size = 118, normalized size = 0.84
method | result | size |
derivativedivides | \(\frac {2 i a^{3} \left (\frac {i B \left (c -i c \tan \left (f x +e \right )\right )^{\frac {3}{2}}}{3}-5 i B c \sqrt {c -i c \tan \left (f x +e \right )}+A c \sqrt {c -i c \tan \left (f x +e \right )}-\frac {4 c^{3} \left (-i B +A \right )}{3 \left (c -i c \tan \left (f x +e \right )\right )^{\frac {3}{2}}}+\frac {4 c^{2} \left (-2 i B +A \right )}{\sqrt {c -i c \tan \left (f x +e \right )}}\right )}{f \,c^{3}}\) | \(118\) |
default | \(\frac {2 i a^{3} \left (\frac {i B \left (c -i c \tan \left (f x +e \right )\right )^{\frac {3}{2}}}{3}-5 i B c \sqrt {c -i c \tan \left (f x +e \right )}+A c \sqrt {c -i c \tan \left (f x +e \right )}-\frac {4 c^{3} \left (-i B +A \right )}{3 \left (c -i c \tan \left (f x +e \right )\right )^{\frac {3}{2}}}+\frac {4 c^{2} \left (-2 i B +A \right )}{\sqrt {c -i c \tan \left (f x +e \right )}}\right )}{f \,c^{3}}\) | \(118\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.30, size = 109, normalized size = 0.78 \begin {gather*} \frac {2 i \, {\left (\frac {4 \, {\left (3 \, {\left (-i \, c \tan \left (f x + e\right ) + c\right )} {\left (A - 2 i \, B\right )} a^{3} - {\left (A - i \, B\right )} a^{3} c\right )}}{{\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac {3}{2}}} + \frac {i \, {\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac {3}{2}} B a^{3} + 3 \, \sqrt {-i \, c \tan \left (f x + e\right ) + c} {\left (A - 5 i \, B\right )} a^{3} c}{c^{2}}\right )}}{3 \, c f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.64, size = 122, normalized size = 0.87 \begin {gather*} -\frac {2 \, \sqrt {2} {\left ({\left (i \, A + B\right )} a^{3} e^{\left (6 i \, f x + 6 i \, e\right )} + 3 \, {\left (-i \, A - 3 \, B\right )} a^{3} e^{\left (4 i \, f x + 4 i \, e\right )} + 12 \, {\left (-i \, A - 3 \, B\right )} a^{3} e^{\left (2 i \, f x + 2 i \, e\right )} + 8 \, {\left (-i \, A - 3 \, B\right )} a^{3}\right )} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}}{3 \, {\left (c^{2} f e^{\left (2 i \, f x + 2 i \, e\right )} + c^{2} f\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - i a^{3} \left (\int \frac {i A}{- i c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )} + c \sqrt {- i c \tan {\left (e + f x \right )} + c}}\, dx + \int \left (- \frac {3 A \tan {\left (e + f x \right )}}{- i c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )} + c \sqrt {- i c \tan {\left (e + f x \right )} + c}}\right )\, dx + \int \frac {A \tan ^{3}{\left (e + f x \right )}}{- i c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )} + c \sqrt {- i c \tan {\left (e + f x \right )} + c}}\, dx + \int \left (- \frac {3 B \tan ^{2}{\left (e + f x \right )}}{- i c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )} + c \sqrt {- i c \tan {\left (e + f x \right )} + c}}\right )\, dx + \int \frac {B \tan ^{4}{\left (e + f x \right )}}{- i c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )} + c \sqrt {- i c \tan {\left (e + f x \right )} + c}}\, dx + \int \left (- \frac {3 i A \tan ^{2}{\left (e + f x \right )}}{- i c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )} + c \sqrt {- i c \tan {\left (e + f x \right )} + c}}\right )\, dx + \int \frac {i B \tan {\left (e + f x \right )}}{- i c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )} + c \sqrt {- i c \tan {\left (e + f x \right )} + c}}\, dx + \int \left (- \frac {3 i B \tan ^{3}{\left (e + f x \right )}}{- i c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )} + c \sqrt {- i c \tan {\left (e + f x \right )} + c}}\right )\, dx\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 10.71, size = 221, normalized size = 1.58 \begin {gather*} \frac {a^3\,\sqrt {\frac {c\,\left (\cos \left (2\,e+2\,f\,x\right )+1-\sin \left (2\,e+2\,f\,x\right )\,1{}\mathrm {i}\right )}{\cos \left (2\,e+2\,f\,x\right )+1}}\,\left (A\,20{}\mathrm {i}+60\,B+A\,\cos \left (2\,e+2\,f\,x\right )\,23{}\mathrm {i}+A\,\cos \left (4\,e+4\,f\,x\right )\,2{}\mathrm {i}-A\,\cos \left (6\,e+6\,f\,x\right )\,1{}\mathrm {i}+69\,B\,\cos \left (2\,e+2\,f\,x\right )+8\,B\,\cos \left (4\,e+4\,f\,x\right )-B\,\cos \left (6\,e+6\,f\,x\right )-7\,A\,\sin \left (2\,e+2\,f\,x\right )-2\,A\,\sin \left (4\,e+4\,f\,x\right )+A\,\sin \left (6\,e+6\,f\,x\right )+B\,\sin \left (2\,e+2\,f\,x\right )\,21{}\mathrm {i}+B\,\sin \left (4\,e+4\,f\,x\right )\,8{}\mathrm {i}-B\,\sin \left (6\,e+6\,f\,x\right )\,1{}\mathrm {i}\right )}{3\,c^2\,f\,\left (\cos \left (2\,e+2\,f\,x\right )+1\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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